TS EAMCET · Maths · Vector Algebra
Let \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) be three unit vectors such that \(\mathbf{a} \times(\mathbf{b} \times \mathbf{c})=\frac{1}{2} \mathbf{b}\). If the angle between \(\mathbf{a}, \mathbf{b}\) is \(\theta_1\) and the angle between \(\mathbf{a}, \mathbf{c}\) is \(\theta_2\), then \(\theta_1+\theta_2\) is equal to
- A \(150^{\circ}\)
- B \(180^{\circ}\)
- C \(120^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(A) \(150^{\circ}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathbf{a} \times(\mathbf{b} \times \mathbf{c})=\frac{1}{2} \mathbf{b} \\ & \Rightarrow (\mathbf{a} \cdot \mathbf{c}) \mathbf{b}-(\mathbf{a} \cdot \mathbf{b}) \mathbf{c}=\frac{1}{2} \mathbf{b} \end{aligned}\) On comparing both sides, we get;…
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