TS EAMCET · Maths · Functions
Let \(f(x)=\mathrm{A} x^2+\mathrm{B} x, g(x)=\mathrm{L} x^2+\mathrm{M} x+\mathrm{N}\). Given that \(f(2)-g(2)=1, f(3)-g(3)=4, f(4)-g(4)=9\). Then a root of \(f(x)-g(x)=0\) is
- A 1
- B -1
- C 0
- D -2
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
We have, \({f}({x})={Ax}^2+{Bx}\) \({g}({x})={Lx}^2+{Mx}+{N}\) now \({f}(2)-{g}(2)=1\) (Given) \({f}(3)-{g}(3)=4\) (Given) \(f(4)-g(4)=9\) (Given) \(\Rightarrow 4(A-L)+2(B-M)-N=1\) ...(i) \(\Rightarrow 9(A- L )+3(B- M )- N =4\) ...(ii) \(\Rightarrow 16(A- L )+4(B- M )- N =9\)…
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