TS EAMCET · Maths · Continuity and Differentiability
Let \(f, g: \mathbf{R} \rightarrow \mathbf{R}\) be functions defined by \(f(x)=\left\{\begin{array}{cc} x \sin \left(\frac{1}{x}\right), & \text { for } x \neq 0 \ 0, & \text { for } x=0 \end{array}\right.\) and \(g(x)=x f(x)\) Consider the following statements (i) \(f(x)\) is continuous at \(x=0\) but not differentiable at \(x=0\) (ii) \(g(x)\) is differentiable at \(x=0\), but \(g^1(x)\) is not continuous at \(x=0\) Then, which one of the following is true?
- A (i) is true; but (ii) is false
- B Both (i) and (ii) are true
- C (i) is false, but (ii) is true
- D Both (i) and (ii) are false
Answer & Solution
Correct Answer
(B) Both (i) and (ii) are true
Step-by-step Solution
Detailed explanation
We have, \(\begin{aligned} & f(x)=\left\{\begin{array}{cc} x \sin \left(\frac{1}{x}\right), & \text { for } x \neq 0 \\ 0, & \text { for } x=0 \end{array}\right. \\ & g(x)=x f(x) \end{aligned}\)…
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