TS EAMCET · Maths · Matrices
Let \(\alpha, \beta, \gamma\) be real numbers. If
\(\left(\begin{array}{ccc}7 & 5 & \alpha \\ \beta & 2 & 11 \\ 3 & \gamma & 1\end{array}\right)\left(\begin{array}{l}1 \\ 3 \\ 2\end{array}\right)=\left(\begin{array}{c}\alpha+\beta \\ -2 \alpha+\beta-2 \gamma \\ \alpha+2 \beta+3 \gamma\end{array}\right)\) then \(100+\frac{2 \alpha+11 \beta}{\gamma}=\)
- A 27
- B -25
- C 225
- D -227
Answer & Solution
Correct Answer
(A) 27
Step-by-step Solution
Detailed explanation
We have \(\left[\begin{array}{ccc}7 & 5 & \lambda \\ \beta & 2 & 11 \\ 3 & \gamma & 1\end{array}\right]\left[\begin{array}{l}1 \\ 3 \\ 2\end{array}\right]=\left[\begin{array}{c}\alpha+\beta \\ -2 \alpha+\beta-2 \gamma \\ \alpha+2 \beta+3 \gamma\end{array}\right]\) On solving we…
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