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TS EAMCET · Maths · Differentiation

Let \(f: R \rightarrow R\) be defined by \(f\left(\frac{x+y}{2}\right)=\frac{f(x)+f(y)}{2}\) for all \(x\) and \(y\). If \(f^{\prime}(0)\) exists and equals -1 and \(f(0)=1\), then \(f(2)=\)

  1. A -1
  2. B 0
  3. C 1/2
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(A) -1

Step-by-step Solution

Detailed explanation

We have, \(f\left(\frac{x+y}{2}\right)=\frac{f(x)+f(y)}{2}\) On differentiating w.r.t. ' \(x\) ', \(y\) as constant \(f^{\prime}\left(\frac{x+y}{2}\right)=\frac{f^{\prime}(x)}{2}\) Put, \(x=0, y=2 x\) we get…