TS EAMCET · Maths · Binomial Theorem
\(1-\frac{3}{16}+\frac{1 \cdot 4}{1 \cdot 2}\left(\frac{3}{16}\right)^2-\frac{1 \cdot 4 \cdot 7}{1 \cdot 2 \cdot 3}\left(\frac{3}{16}\right)^3+\ldots\)
- A \(\left(\frac{15}{6}\right)^{3 / 8}\)
- B \(\left(\frac{4}{5}\right)^{2 / 3}\)
- C \(\left(\frac{7}{4}\right)^{1 / 16}\)
- D \(\left(\frac{4}{15}\right)^{-2 / 5}\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{4}{5}\right)^{2 / 3}\)
Step-by-step Solution
Detailed explanation
We have, \(1-\frac{3}{16}+\frac{1 \cdot 4}{1 \cdot 2}\left(\frac{3}{16}\right)^2-\frac{1 \cdot 4 \cdot 7}{1 \cdot 2 \cdot 3}\left(\frac{3}{16}\right)^3+\ldots=\) We know that, \((1-x)^n=1-n x+\frac{n(n-1)}{2 !} x^2-\frac{n(n-1)(n-2)}{3 !} x^3\) Let…
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