TS EAMCET · Maths · Parabola
The cartesian equation of the parabola \(x=-2+2 t^2\), \(y=2+4 t\) is
- A \(y^2-8 x-4 y+12=0\)
- B \(y^2-8 x-4 y-12=0\)
- C \(y^2+8 x-4 y-12=0\)
- D \(y^2-8 x+4 y-12=0\)
Answer & Solution
Correct Answer
(B) \(y^2-8 x-4 y-12=0\)
Step-by-step Solution
Detailed explanation
Given equation is \(x=-2+2 t^2, y=2+4 t\). From, \(y=2+4 t\) \[ t=\frac{(y-2)}{4} \] Put in equation \(x=-2+2 t^2\)…
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