TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(\frac{5 \sinh 2 x}{7+6 \cosh 2 x}=\frac{3}{2}\), then \(3 \tan \mathrm{h}^2 x+20 \tan \mathrm{h} x=\)
- A 13
- B 26
- C 39
- D \(\frac{13}{2}\)
Answer & Solution
Correct Answer
(C) 39
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{5 \sinh 2 x}{7+6 \cosh 2 x}=\frac{3}{2} \\ & \Rightarrow \frac{10 \sinh x \cdot \operatorname{coshx}}{7+6\left(2 \cosh ^2 x-1\right)}=\frac{3}{2} \\ & \Rightarrow \frac{10 \sinh x \cdot \cosh x}{12 \cosh ^2 x+1}=\frac{3}{2} \\ & \Rightarrow \frac{10 \tanh…
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