TS EAMCET · Maths · Quadratic Equation
\(\alpha, \beta, \gamma\) are the roots of the cubic equation \(x^3+p_1 x^2+p_2 x+p_3=0\). If \(S_\gamma=\alpha^\gamma+\beta^\gamma+\gamma^\gamma\), \(S_1=10, S_2=38\) and \(S_3=-1840\), then \(p_3=\)
- A -30
- B \(\frac{1910}{3}\)
- C 631
- D -31
Answer & Solution
Correct Answer
(B) \(\frac{1910}{3}\)
Step-by-step Solution
Detailed explanation
We have, \(\alpha, \beta, \gamma\) are roots of equation \[ \begin{aligned} x^3+p_1 x^2+p_2 x+p_3 & =0 \\ S_r & =\alpha^\mu+\beta^r+\gamma^r \\ S_1 & =\alpha+\beta+\gamma=10 \\ S_2 & =\alpha^2+\beta^2+\gamma^2=38 \\ S_3 & =\alpha^3+\beta^3+\gamma^3=-1840 \end{aligned} \] Now,…
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