TS EAMCET · Maths · Definite Integration
then
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Let l=limn→∞1nlog2n!nnn! Note: Assume base of logarithm as e l=limn→∞1nlogn+1n+2.....n+nnn ⇒l=limx→∞1n∑r=1nlogn+rn ⇒l=limx→∞1n∑r=1nlog1+rn ⇒l=∫01log1+xdx put x+1=t ⇒dx=dt…
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