TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The correct order of ionic radii for the given species is
- A \(\mathrm{Na}^{+}>\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}\)
- B \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}\)
- C \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}\)
- D \(\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}>\mathrm{Na}^{+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}\)
Step-by-step Solution
Detailed explanation
Ionic radii of isoelectronic ions decreases with increase in the magnitude of nuclear charge. If the species is positively charged, then it has less ionic radii. Therefore; the correct order of ionic radii is \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\)…
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