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TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties

The correct order of ionic radii for the given species is

  1. A \(\mathrm{Na}^{+}>\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}\)
  2. B \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}\)
  3. C \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}\)
  4. D \(\mathrm{Al}^{3+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}>\mathrm{Na}^{+}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}\)

Step-by-step Solution

Detailed explanation

Ionic radii of isoelectronic ions decreases with increase in the magnitude of nuclear charge. If the species is positively charged, then it has less ionic radii. Therefore; the correct order of ionic radii is \(\mathrm{K}^{+}>\mathrm{Na}^{+}>\)…