TS EAMCET · Maths · Three Dimensional Geometry
Let \(\pi_1\) be the plane passing through the points \((0,1,2),(1,0,-2),(-2,1,0)\) and \(\pi_2\) be the plane passing through the point \((1,2,3)\) and perpendicular to the planes \(x+y+z=1\) and \(2 x-3 y+z=5\). If \(\theta\) is the acute angle between the planes \(\pi_1\) and \(\pi_2\), then \(\cos \theta=\)
- A \(\frac{\sqrt{14}}{9}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{13}{3 \sqrt{22}}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{14}}{9}\)
Step-by-step Solution
Detailed explanation
Equation of the plane \(\pi_1\) passing through the three non-collinear points \((0,1,4,(1,0,-4)\) and \((-2,1,0)\) is…
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