TS EAMCET · Maths · Straight Lines
\(\mathrm{L} \equiv 7 \mathrm{x}-\mathrm{y}+8=0\) is one of the diagonals of a square for which \((-4,5),(3,4)\) are two vertices. Then the coordinates of the two vertices lying on the diagonal \(\mathrm{L}=0\) are
- A \((0,8),(-1,1)\)
- B \((-1,1),(0,8)\)
- C \((-2,-6),(1,15)\)
- D \((1,3),(-2,-6)\)
Answer & Solution
Correct Answer
(A) \((0,8),(-1,1)\)
Step-by-step Solution
Detailed explanation
\(\text{Midpoint of given vertices: } M = \left(\frac{-4+3}{2}, \frac{5+4}{2}\right) = \left(-\frac{1}{2}, \frac{9}{2}\right)\) \(\text{Square of diagonal length: } d^2 = (3 - (-4))^2 + (4 - 5)^2 = 7^2 + (-1)^2 = 49 + 1 = 50\)…
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