TS EAMCET · Maths · Differentiation
If \(z=\frac{y}{x}\left[\sin \frac{x}{y}+\cos \left(1+\frac{y}{x}\right)\right]\), then \(x \frac{\partial z}{\partial x}\) is equal to
- A \(y \frac{\partial z}{\partial y}\)
- B \(-y \frac{\partial z}{\partial y}\)
- C \(2 y \frac{\partial z}{\partial y}\)
- D \(2 y \frac{\partial z}{\partial x}\)
Answer & Solution
Correct Answer
(B) \(-y \frac{\partial z}{\partial y}\)
Step-by-step Solution
Detailed explanation
We have, \[ z=\frac{y}{x}\left[\sin \frac{x}{y}+\cos \left(1+\frac{y}{x}\right)\right] \]…
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