TS EAMCET · Maths · Three Dimensional Geometry
In a triangle \(A B C\), if the mid points of sides \(A B, B C\), CA are \((3,0,0),(0,4,0),(0,0,5)\) respectively, then \(\mathrm{AB}^2+\mathrm{BC}^2+\mathrm{CA}^2=\)
- A \(50\)
- B \(200\)
- C \(300\)
- D \(400\)
Answer & Solution
Correct Answer
(D) \(400\)
Step-by-step Solution
Detailed explanation
\(x_1+x_2=6\) \( \begin{aligned} & x_2+x_3=0 \\ & x_1+x_3=0 \\ & \therefore x_1=x_2=3 \\ & x_1=-3 \end{aligned} \) Similarly…
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