TS EAMCET · Maths · Permutation Combination
A student is asked to answer 10 out of 13 questions is an examination such that he must answer atleast four questions from the first five questions. The number of choices available to him is
- A 140
- B 176
- C 196
- D 280
Answer & Solution
Correct Answer
(C) 196
Step-by-step Solution
Detailed explanation
Case I 4 questions from first 5 questions and 6 questions from remaining 8 questions \[ \therefore \quad{ }^5 C_4 \times{ }^8 C_6=5 \times 28=140 \] Case II Choose 5 questions from first 5 questions and next 5 questions from remaining 8 questions…
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