TS EAMCET · Maths · Probability
In a family with 4 children, the probability that there are atleast two girls, is
- A \(\frac{1}{2}\)
- B \(\frac{9}{16}\)
- C \(\frac{3}{4}\)
- D \(\frac{11}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{11}{16}\)
Step-by-step Solution
Detailed explanation
Total number of outcomes \(=2^4=16\) Let \(X\) be the number of girls. Now, probability (atleast two girls) \[ =1-\{P(X=0)+P(X=1)\} \] \(P(X=0)\), i.e. no girl or all boys. Favourable outcome \(=\{B B B B\}=1\)…
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