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TS EAMCET · Maths · Definite Integration

\(\int_{-1}^1 \frac{\log 2-\log (1+x)}{\sqrt{1-x^2}} d x=\)

  1. A \(\frac{\pi}{8} \log 2\)
  2. B \(-\frac{\pi}{2} \log 2\)
  3. C \(-\frac{\pi}{4} \log 2\)
  4. D \(2 \pi \log 2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \pi \log 2\)

Step-by-step Solution

Detailed explanation

\(\int_{-1}^1 \frac{\log 2}{\sqrt{1-x^2}} d x - \int_{-1}^1 \frac{\log (1+x)}{\sqrt{1-x^2}} d x\) \(\int_{-1}^1 \frac{\log 2}{\sqrt{1-x^2}} d x = \log 2 [\arcsin x]_{-1}^1 = \log 2 (\frac{\pi}{2} - (-\frac{\pi}{2})) = \pi \log 2\) Let…