TS EAMCET · Maths · Properties of Triangles
In \(\triangle A B C\), if \(\angle C=\frac{\pi}{3}\), then \(\frac{3}{a+b+c}-\frac{1}{a+c}\) equals
- A \(\frac{1}{a+b}\)
- B \(\frac{1}{b+c}\)
- C \(\frac{1}{2 a+b}\)
- D \(\frac{1}{b+2 c}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{b+c}\)
Step-by-step Solution
Detailed explanation
We have, \(\angle C=\frac{\pi}{3}\) Now, \(\quad \cos C=\frac{a^2+b^2-c^2}{2 a b}\)…
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