TS EAMCET · Maths · Properties of Triangles
In \(\triangle A B C\), if \(A\) is an acute angle, \(b=6, c=9\) and \(\sin\) \(A=\frac{2 \sqrt{14}}{9}\), then \(3 \mathrm{a}(\cos \mathrm{B}+\cos \mathrm{C})=\)
- A \(14\)
- B \(20\)
- C \(17\)
- D \(23\)
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
\(b=6, c=9\)…
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