TS EAMCET · Maths · Parabola
If \(\overrightarrow{A B}\) is the focal chord of the parabola \(y^2=16 x\) and \(A=(1,-4)\), then the equation of the normal to the parabola at the point \(\mathrm{B}\) is
- A \(2 x+y-32=0\)
- B \(2 x+y-48=0\)
- C \(x-2 y+16=0\)
- D \(x+2 y-48=0\)
Answer & Solution
Correct Answer
(B) \(2 x+y-48=0\)
Step-by-step Solution
Detailed explanation
If parameter of \(A\) and \(B\) are \(t_1, t_2\) then \(t_1 \cdot t_2=-1\)…
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