TS EAMCET · Maths · Functions
If \(\alpha, \beta, \gamma, \delta\) are the roots of the equation \(x^4-8 x^3+11 x^2+32 x-60=0\) and \(\alpha < \beta < \gamma < \delta\), then \(4 \alpha+3 \beta+2 \gamma+\delta=\)
- A \(0\)
- B \(1\)
- C \(9\)
- D \(10\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
We have, \(\begin{aligned} x^4-8 x^3+11 x^2+32 x-60 & =0 \\ \Rightarrow \quad(x+2)(x-2)(x-3)(x-5) & =0\end{aligned}\) \(\therefore \quad \alpha=-2, \beta=2, \gamma=3, \delta=5\)…
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