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TS EAMCET · Maths · Functions

If \(\alpha, \beta, \gamma, \delta\) are the roots of the equation \(x^4-8 x^3+11 x^2+32 x-60=0\) and \(\alpha < \beta < \gamma < \delta\), then \(4 \alpha+3 \beta+2 \gamma+\delta=\)

  1. A \(0\)
  2. B \(1\)
  3. C \(9\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(9\)

Step-by-step Solution

Detailed explanation

We have, \(\begin{aligned} x^4-8 x^3+11 x^2+32 x-60 & =0 \\ \Rightarrow \quad(x+2)(x-2)(x-3)(x-5) & =0\end{aligned}\) \(\therefore \quad \alpha=-2, \beta=2, \gamma=3, \delta=5\)…