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TS EAMCET · Maths · Properties of Triangles

If in a \(\triangle A B C, \frac{1}{a+c}+\frac{1}{b+c}=\frac{3}{a+b+c}\), then \(\angle C\) is equal to

  1. A \(30^{\circ}\)
  2. B \(45^{\circ}\)
  3. C \(60^{\circ}\)
  4. D \(90^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(60^{\circ}\)

Step-by-step Solution

Detailed explanation

In \(\triangle A B C\) \[ \frac{1}{a+c}+\frac{1}{b+c}=\frac{3}{a+b+c} \] Let \(\angle C=60^{\circ}\), then \[ \cos C=\frac{\pi}{3} \]…