TS EAMCET · Maths · Properties of Triangles
\(\text { In a } \triangle A B C, \frac{\Delta^2}{a^2+b^2+c^2}\left(\frac{1}{r_1^2}+\frac{1}{r_2^2}+\frac{1}{r_3^2}+\frac{1}{r^2}\right)=\)
- A 0
- B 1
- C \(\Delta\)
- D \(\mathrm{S}\)
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\(\frac{\Delta^2}{a^2+b^2+c^2}\left(\frac{1}{r_1^2}+\frac{1}{r_2^2}+\frac{1}{r_3^2}+\frac{1}{r^2}\right)\) \(=\frac{\Delta^2}{a^2+b^2+c^2}\left[\frac{(s-a)^2}{\Delta^2}+\frac{(s-b)^2}{\Delta^2}+\frac{(s-c)^2}{\Delta^2}+\frac{s^2}{\Delta^2}\right]\)…
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