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TS EAMCET · Maths · Ellipse

If the extremities of the latus recta having positive ordinate of the ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a \gt b)\) lie on the parabola \(x^2+2 a y-4=0\), then the points \((a, b)\) lie on the curve

  1. A \(x y=4\)
  2. B \(x^2+y^2=4\)
  3. C \(\frac{x^2}{4}+\frac{y^2}{1}=1\)
  4. D \(\frac{x^2}{4}-\frac{y^2}{1}=1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x^2+y^2=4\)

Step-by-step Solution

Detailed explanation

Extermities \(\left( \pm a e, \frac{b^2}{a}\right)\) put in \(x^2+2 a y-4=0\)…