TS EAMCET · Maths · Ellipse
If the extremities of the latus recta having positive ordinate of the ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a \gt b)\) lie on the parabola \(x^2+2 a y-4=0\), then the points \((a, b)\) lie on the curve
- A \(x y=4\)
- B \(x^2+y^2=4\)
- C \(\frac{x^2}{4}+\frac{y^2}{1}=1\)
- D \(\frac{x^2}{4}-\frac{y^2}{1}=1\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2=4\)
Step-by-step Solution
Detailed explanation
Extermities \(\left( \pm a e, \frac{b^2}{a}\right)\) put in \(x^2+2 a y-4=0\)…
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