TS EAMCET · Maths · Complex Number
If \(Z=x+i y\) is a complex number and \(\sqrt{x^2-2 x+8}+(x+4) i=y(2+i)\), then \(Z\) is equal to
- A \(\frac{-28}{9}-\frac{16}{9} i\)
- B \(-2+2 i\)
- C \(\frac{2}{3}-\frac{2}{3} i\)
- D \(\frac{-2}{5}-\frac{2 i}{5}\)
Answer & Solution
Correct Answer
(B) \(-2+2 i\)
Step-by-step Solution
Detailed explanation
Given, \(\sqrt{x^2-2 x+8}+(x+4) i=y(2+i)\) On equating real and imaginary parts,…
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