TS EAMCET · Maths · Complex Number
If \(z_1\) and \(z_2\) are the roots of the equation \(x^2+2 x+2=0\), then \(\frac{-2^{11}\left(z_1+1+3 i\right)^{11}}{2^5\left(z_2+1-3 i\right)^{11}}\) is equal to
- A 64
- B 32
- C \(16 \sqrt{2}\)
- D \(8 \sqrt{2}\)
Answer & Solution
Correct Answer
(A) 64
Step-by-step Solution
Detailed explanation
\(z_1\) and \(z_2\) are the roots of \(x^2+2 x+2=0\) \( \therefore z_1+z_2=-2 \Rightarrow z_2=-2-z_1 \) \(\Rightarrow \quad 2 z_2=-2 z_1-4\) ...(i)…
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