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TS EAMCET · Maths · Differentiation

If \(\sqrt{\frac{y}{x}}+\sqrt{\frac{x}{y}}=2\), then \(\frac{d y}{d x}\) is equal to

  1. A \(\frac{x^2+y^2}{x+y}\)
  2. B \(\frac{x^2-y^2}{x+y}\)
  3. C \(1\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

We have \(\sqrt{\frac{y}{x}}+\sqrt{\frac{x}{y}}=2\) \[ \Rightarrow \quad y+x=2 \sqrt{x} \cdot \sqrt{y} \] On squaring both sides, we get…