TS EAMCET · Maths · Statistics

The means of two groups of observations $A$ and $B$ are $\vec{x}, \vec{y}$ respectively and their standard deviations are respectively $2$ and $3 .$ In order that the group $A$ is to be more consistent than the group $B,$ $\frac{\vec{y}}{\vec{x}} <$

A $\frac{3}{2}$
B $\frac{5}{1}$
C $\frac{2}{3}$
D $\frac{6}{5}$

Verified Solution

Answer & Solution

Correct Answer

(A) $\frac{3}{2}$

Step-by-step Solution

Detailed explanation

We know, coefficient of variation =σx→×100Given that, the group A is more consistent than the group B, So, coefficient of variation of A<coefficient of variation of B Then, Aσx→<Bσy→…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From TS EAMCET

Explore more questions on app

The means of two groups of observations A and B are x→, y→ respectively and their standard deviations are respectively 2 and 3. In order that the group A is to be more consistent than the group B, y→x→<

Step-by-step Solution

The means of two groups of observations $A$ and $B$ are $\vec{x}, \vec{y}$ respectively and their standard deviations are respectively $2$ and $3 .$ In order that the group $A$ is to be more consistent than the group $B,$ $\frac{\vec{y}}{\vec{x}} <$