TS EAMCET · Maths · Differentiation
If \(y=\frac{\tan x \cos ^{-1} x}{\sqrt{1-x^2}}\) then the value of \(\frac{d y}{d x}\), when \(x=0\) is
- A 0
- B \(\frac{\pi}{2}\)
- C 1
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
\(y=\frac{\tan x \cos ^{-1} x}{\sqrt{1-x^2}}\)…
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