TS EAMCET · Chemistry · Structure of Atom
If the electron of a hydrogen atom is present in the first orbit, the total energy of the electron is
- A \(\frac{-e^2}{r}\)
- B \(\frac{-e^2}{r^2}\)
- C \(\frac{-e^2}{2 r}\)
- D \(\frac{-e^2}{2 r^2}\)
Answer & Solution
Correct Answer
(C) \(\frac{-e^2}{2 r}\)
Step-by-step Solution
Detailed explanation
Kinetic energy \(=\frac{1}{2} m v^2\) Potential energy \(=\frac{-e^2}{r}\) But \(m v^2=\frac{e^2}{r}\) \(\mathrm{KE}=\frac{1}{2} \frac{e^2}{r}\) Total energy \(=\mathrm{KE}+\mathrm{PE}\)…
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