TS EAMCET · Maths · Matrices
If \(x=\alpha, y=\beta, z=\gamma\) is the solution of the system of equations \(2 x+3 y+z=-1\), \(3 x+y+z=4, x-3 y-2 z=1\), then the value of \(\beta\) is
- A \(-2\)
- B \(-1\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(-2\)
Step-by-step Solution
Detailed explanation
\(Eq2 - Eq1 \Rightarrow x-2y=5\) (Eq4) \(2 \cdot Eq1 + Eq3 \Rightarrow 5x+3y=-1\) (Eq5) From \(Eq4, x = 5+2y\). Substitute into \(Eq5\): \(5(5+2y)+3y = -1\) \(25+10y+3y = -1\) \(13y = -26\) \(y = -2\) \(\beta = -2\)
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