TS EAMCET · Maths · Properties of Triangles
The greatest angle of the triangle whose sides are \(x^2+x+1,2 x+1\) and \(x^2-1\) is
- A \(75^{\circ}\)
- B \(90^{\circ}\)
- C \(105^{\circ}\)
- D \(120^{\circ}\)
Answer & Solution
Correct Answer
(D) \(120^{\circ}\)
Step-by-step Solution
Detailed explanation
Among \(x^2+x+1,2 x+1, x^2-1\), the largest value is \(x^2+x+1\). \(\therefore\) Greatest angle with the angle opposite to the side \(x^2+x+1\). Let it be \(\theta\).…
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