TS EAMCET · Maths · Binomial Theorem
If \(x\) is so small that \(x^2\) and higher powers of \(x\) may be neglected, then the approximate value of \(\frac{\left(1+\frac{2}{3} x\right)^{-3}(1-15 x)^{-1 / 5}}{(2-3 x)^4}\)
- A \(\frac{1}{8}(1+7 x)\)
- B \(\frac{1}{16}(1-7 x)\)
- C \(1-7 x\)
- D \(\frac{1}{16}(1+7 x)\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{16}(1+7 x)\)
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