TS EAMCET · Maths · Permutation Combination
A man has 7 relatives, 4 of them are ladies and 3 gents; his wife has 7 other relatives, 3 of them are ladies and 4 gents. The number of ways they can invite them to a party of 3 ladies and 3 gents so that there are 3 of man's relatives and 3 of wife's relatives, is
- A 341
- B 161
- C 485
- D 435
Answer & Solution
Correct Answer
(C) 485
Step-by-step Solution
Detailed explanation
If 3 man's relatives are gents and 3 wife's relatives are ladies. Number of ways \(={ }^3 \mathrm{C}_3 \times{ }^4 \mathrm{C}_0 \times{ }^3 \mathrm{C}_3 \times{ }^4 \mathrm{C}_0=\left({ }^3 \mathrm{C}_3\right)^2 \times\left({ }^4 \mathrm{C}_0\right)^2\) If 3 man's relatives have…
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