ExamBro
ExamBro
TS EAMCET · Maths · Hyperbola

If the tangent drawn at a point \(\mathrm{P}(t)\) on the hyperbola \(x^2-y^2=c^2\) cuts \(X\)-axis at T and the normal drawn at the same point \(P\) cuts the Y -axis at N , then the equation of the locus of the midpoint of TN is

  1. A \(\frac{c^2}{4 x^2}-\frac{y^2}{c^2}=1\)
  2. B \(\frac{x^2}{c^2}-\frac{y^2}{4 c^2}=1\)
  3. C \(\frac{x^2}{4 c^2}+\frac{y^2}{c^2}=1\)
  4. D \(x^2+y^2=4 c^2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{c^2}{4 x^2}-\frac{y^2}{c^2}=1\)

Step-by-step Solution

Detailed explanation

Let \(\mathrm{P}(\mathrm{t})=\mathrm{ct}\) Then \(\left(c t, \sqrt{c^2 t^2-c^2}\right)\) lies on hyperbola \(x^2-y^2=c^2\) Equation of tangent \(=x c t-y\left(\sqrt{c^2 t^2-c^2}\right)=c^2\) x -intercept of tangent \(=\mathrm{T}=\frac{c}{t}\) Equation of normal…