TS EAMCET · Maths · Probability
A fair coin is tossed a fixed number of times. If the probability of getting 5 heads is equal to the probability of getting 4 heads, then the probability of getting 6 heads is
- A \(\frac{7}{64}\)
- B \(\frac{9}{32}\)
- C \(\frac{21}{128}\)
- D \(\frac{35}{256}\)
Answer & Solution
Correct Answer
(C) \(\frac{21}{128}\)
Step-by-step Solution
Detailed explanation
Here \(p(H)=\frac{1}{2}=p, q=\frac{1}{2}\) According to question,…
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