TS EAMCET · Maths · Circle
The length of the common chord of the two circles \(x^2+y^2-4 x-8 y+4=0\) and \(x^2+y^2-8 x-12 y+16=0\) is
- A \(\sqrt{46}\)
- B \(\sqrt{15}\)
- C \(\sqrt{55}\)
- D 3
Answer & Solution
Correct Answer
(A) \(\sqrt{46}\)
Step-by-step Solution
Detailed explanation
Given equations of circles are \(x^2+y^2-4 x-8 y+4\) \(=0\) and \(x^2+y^2-8 x-12 y+16=0\) Equation of common chord \(=\mathrm{S}_1-\mathrm{S}_2\) \(=\quad x^2+y^2-4 x-8 y+4-x^2-y^2+8 x+12 y-16\)…
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