TS EAMCET · Maths · Differential Equations
If the solution \(y(x)\) of the differential equation \(\sin x \frac{d y}{d x}+y \cos x=e^{2 x}, x \in(0, \pi)\) satisfies \(y\left(\frac{\pi}{2}\right)=0\), then \(y\left(\frac{\pi}{6}\right)=\)
- A \(e^{\pi / 3}+e^\pi\)
- B \(e^{\pi / 3}-e^\pi\)
- C \(e^\pi-e^{\pi / 3}\)
- D \(\frac{1}{2}\left(e^{\pi / 3}-e^\pi\right)\)
Answer & Solution
Correct Answer
(B) \(e^{\pi / 3}-e^\pi\)
Step-by-step Solution
Detailed explanation
Given differential equation, \(\sin x \frac{d y}{d x}+y \cos x=e^{2 x}, x \in(0, \pi)\) or \(\quad \frac{d y}{d x}+y \cot x=\frac{e^{2 x}}{\sin x}\) This is linear differential equation and general form is given by \(\frac{d y}{d x}+P(x) y=Q(x) Here \)P(x)=\cot x,…
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