TS EAMCET · Maths · Pair of Lines
If the pair of straight lines \(x y-x-y+1=0\) and the line \(a x+2 y-3 a=0\) are concurrent, then \(a\) is equal to
- A \(0\)
- B \(1\)
- C \(-1\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{array}{r} x y-x-y+1=0 \\ a x+2 y-3 a=0 \end{array} \] and Eqs. (i) with, On comparing Eqs. (i) with, \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\), we get \(a=0, b=0, h=\frac{1}{2}, g=-\frac{1}{2}, f=-\frac{1}{2}, c=1\) The point of concurrent is…
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