TS EAMCET · Maths · Matrices
If \(A=\left[\begin{array}{rr}-8 & 5 \\ 2 & 4\end{array}\right]\) satisfies the equation \(x^2+4 x-p=0\), then \(p\) is equal to
- A \(64\)
- B \(42\)
- C \(36\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(42\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & =\left[\begin{array}{rr}64+10 & -40+20 \\ -16+8 & 10+16\end{array}\right] \\ & =\left[\begin{array}{ll}74 & -20 \\ -8 & 26\end{array}\right] \\ & 4 A=\left[\begin{array}{rr}-32 & 20 \\ 8 & 16\end{array}\right] \\ & -p l=\left[\begin{array}{cc}-p & 0 \\ 0 &…
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