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TS EAMCET · Maths · Circle

For all real values of \(k\), the point which lies on the polar of \((k, k+1)\) with respect to the circle \(x^2+y^2+4 x-8 y-5=0\) is

  1. A \((3,-1)\)
  2. B \((3,1)\)
  3. C \((2,-2)\)
  4. D \((2,3)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((3,-1)\)

Step-by-step Solution

Detailed explanation

\(\because\) polor of \((k, k+1)\) At \(x^2+y^2+4 x-8 y-5=0\) is Equation of polar \(=T=0\)…