TS EAMCET · Maths · Circle
For all real values of \(k\), the point which lies on the polar of \((k, k+1)\) with respect to the circle \(x^2+y^2+4 x-8 y-5=0\) is
- A \((3,-1)\)
- B \((3,1)\)
- C \((2,-2)\)
- D \((2,3)\)
Answer & Solution
Correct Answer
(A) \((3,-1)\)
Step-by-step Solution
Detailed explanation
\(\because\) polor of \((k, k+1)\) At \(x^2+y^2+4 x-8 y-5=0\) is Equation of polar \(=T=0\)…
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