TS EAMCET · Maths · Straight Lines
The distance between the parallel lines given by \((x+7 y)^2+4 \sqrt{2}(x+7 y)-42=0\) is
- A \(\frac{4}{5}\)
- B \(4 \sqrt{2}\)
- C \(2\)
- D \(10 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
Given equation is \((x+7 y)^2+4 \sqrt{2}(x+7 y)-42=0\) Put \(x+7 y=t\)…
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