TS EAMCET · Maths · Straight Lines
If the lines drawn along the diagonals of the two squares formed by two pairs of lines \(x^2-3|x|+2=0\) and \(y^2-3 y+2=0\) form a square \(A B C D\), then the equations of two adjacent sides of the square \(A B C D\) are
- A \(x+y=-3, x-y=3\)
- B \(x+y=0, x-y=3\)
- C \(x+y=3, x-y=-3\)
- D \(x-y=0, x+y=-3\)
Answer & Solution
Correct Answer
(C) \(x+y=3, x-y=-3\)
Step-by-step Solution
Detailed explanation
\(\begin{gathered}\text { Given, } x^2-3|x|+2=0 \\ \qquad \begin{array}{c}(|x|-2)(|x|-1)=0 \\ |x|=2 \text { or }|x|=1 \\ x= \pm 2 \text { or } x= \pm 1\end{array}\end{gathered}\) and \(\begin{aligned} y^2-3 y+2 & =0 \\ (y-2)(y-1) & =0 \\ y & =2,1 \end{aligned}\) \(\Rightarrow\)…
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