TS EAMCET · Maths · Circle
If the lines \(3 x+4 y-14=0\) and \(6 x+8 y+7=0\) are both tangents to a circle, then its radius is
- A 7
- B \(\frac{7}{2}\)
- C \(\frac{7}{4}\)
- D \(\frac{7}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{7}{4}\)
Step-by-step Solution
Detailed explanation
Given, lines are both tangents to a circle we observe that, both lines are parallel i.e., \(\begin{aligned} 3 x+4 y-14 & =0 \\ 3 x+4 y+\frac{7}{2} & =0 \end{aligned}\) So, radius of circle \(=\frac{1}{2}\) (distance between two parallel lines)…
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