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TS EAMCET · Maths · Differential Equations

If the length of the sub tangent at any point \(p(x, y)\) on a curve \(f(x, y)=0\) is \(x+7 y^2\), then \(f(x, y)=\)

  1. A \(x y+c y-7 x\)
  2. B \(\frac{x}{y}+7 x-c\)
  3. C \(7 y^2+c y-x\)
  4. D \(7 x y+c y-x\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(7 y^2+c y-x\)

Step-by-step Solution

Detailed explanation

(c) We know that, Length of subtangent \(=\frac{y}{\frac{d y}{d x}} \Rightarrow x+7 y^2=\frac{y}{\frac{d y}{d x}}\)…