TS EAMCET · Maths · Three Dimensional Geometry
If the equation of the plane passing through the point \((2,-1,3)\) and perpendicular to the planes \(3 x-2 y+z=9\) and \(x+y+z=9\) is \(x+b y+c z+d=0\), then \(d=\)
- A \(\frac{11}{3}\)
- B 0
- C 3
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{11}{3}\)
Step-by-step Solution
Detailed explanation
Required plane passes through \((2,-1,3)\). Let \(a, b\) and \(c\) are Dr's of normal to required plane. Equation of required plane \[ a(x-2)+b(y+1)+c(z-3)=0 \] Since, plane \(\perp\) to \(3 x-2 y+z=9\) \(\therefore \quad 3 a-2 b+c=0\)…
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