TS EAMCET · Maths · Differential Equations
If the equation of the curve which passes through the point \((1,1)\) satisfies the differential equation \(\frac{d y}{d x}=\frac{2 x-5 y+3}{5 x+2 y-3}\). then the equation of that curve is
- A \(x^2+5 x y-y^2+3 x-3 y-5=0\)
- B \(x^2+5 x y-y^2+3 x+3 y-11=0\)
- C \(x^2-5 x y-y^2-3 x-3 y+11=0\)
- D \(x^2-5 x y-y^2+3 x+3 y-1=0\)
Answer & Solution
Correct Answer
(D) \(x^2-5 x y-y^2+3 x+3 y-1=0\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{d y}{d x}=\frac{2 x-5 y+3}{5 x+2 y-3} \\ \Rightarrow & 5 x d y+2 y d y-3 d y=2 x d x-5 y d x+3 d x \\ \Rightarrow & 5(x d y+y d x)+d\left(y^2\right)-3 d y=2 x d x+3 d x \\ \Rightarrow & 5 d(x y)+d\left(y^2\right)-3 d y=d\left(x^2\right)+3 d x \\…
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