TS EAMCET · Maths · Pair of Lines
The equation of the pair of bisectors of the triangle between the pair of straight lines \(3 x^2+7 x y+2 y^2+5 x+5 y+2=0\) is
- A \(7(3 x+5)^2-2(3 x+5)(y+5)-7(y+5)^2=0\)
- B \(7(3 x-5)^2-2(3 x-5)(y-5)-7(y-5)^2=0\)
- C \(7(5 x+3)^2-2(5 x+3)(5 y+1)-7(5 y+1)^2=0\)
- D \(7(5 x-3)^2-2(5 x-3)(5 y-1)-7(5 y-1)^2=0\)
Answer & Solution
Correct Answer
(C) \(7(5 x+3)^2-2(5 x+3)(5 y+1)-7(5 y+1)^2=0\)
Step-by-step Solution
Detailed explanation
Given, pair of straight line \[ 3 x^2+7 x y+2 y^2+5 x+5 y+2=0 \] The pair of straight line are \[ (3 x+y+2)(x+2 y+1)=0 \] Intersection point of lines are \(\left(\frac{-3}{5}, \frac{-1}{5}\right)\) \(\therefore\) Angle bisector of line are…
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