TS EAMCET · Maths · Area Under Curves
If the area of the region bounded by \(y=\cos x\), \(y=\sin x, x=\frac{\pi}{4}\) and \(x=\pi\) is bisected by the line \(x=a\), then \(\sin \left(a+\frac{\pi}{4}\right)=\)
- A \(\frac{\sqrt{2}}{2+\sqrt{2}}\)
- B \(\frac{\sqrt{3}+1}{2}\)
- C \(\frac{\sqrt{2}-1}{2 \sqrt{2}}\)
- D \(\frac{\sqrt{3}+1}{2 \sqrt{2}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\sqrt{2}-1}{2 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
According to the question, \(\int_{\frac{\pi}{4}}^a(\sin x-\cos x) d x=\int_a^\pi(\sin x-\cos x) d x\)…
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